0.7x^2=-1.3+2.3x

Solution for 0.7x^2=-1.3+2.3x equation:

0.7x^2=-1.3+2.3x

We move all terms to the left:

0.7x^2-(-1.3+2.3x)=0

We add all the numbers together, and all the variables

0.7x^2-(2.3x-1.3)=0

We get rid of parentheses

0.7x^2-2.3x+1.3=0

a = 0.7; b = -2.3; c = +1.3;
Δ = b2-4ac
Δ = -2.32-4·0.7·1.3
Δ = 1.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.3)-\sqrt{1.65}}{2*0.7}=\frac{2.3-\sqrt{1.65}}{1.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.3)+\sqrt{1.65}}{2*0.7}=\frac{2.3+\sqrt{1.65}}{1.4}
$